(Paper) Wipro Paper Pattern

WIPRO Placement Paper

PART A

1) abcD+abcd+aBCd+aBCD then the simplified function is ( Capital letters are copliments of corresponding letters A=compliment of a)
[a] a
[b] ab
[c] abc
[d] a(bc)*
[e] None (bc)*=compliment of bc 
Ans: e 

2) A 12 address lines maps to the memory of 
[a] 1k bytes
[b] 0.5k bytes
[c] 2k bytes
[d] none 
Ans: b 
 

3) In a processor these are 120 instructions . Bits needed to implement this instructions 
[a] 6
[b] 7
[c] 10
[d] none 
Ans: b 
 

4) In 8085 microprocessor READY signal does.which of the following is incorrect statements
[a] It is input to the microprocessor
[b] It sequences the instructions. 
Ans : b 
 
5) Return address will be returned by function to :
Ans : Pushes to the stack by call 


6) n=7623 
{temp=n/10; result=temp*10+ result; n=n/10 } 
Ans : 3267 
 
7) If A>B then 
F=F(G); 
else B>C then 
F=G(G); 
in this , for 75% times A>B and 25% times B>C then,is 10000 instructions are there ,then the ratio of F to G 
[a] 7500:2500
[b] 7500:625
[c] 7500:625 if a=b=c else 7500:2500 
 
8) In a compiler there is 36 bit for a word and to store a character 8bits are needed. IN this to store a character two words are appended .Then for storing a K characters string, How many words are needed. 
[a] 2k/9
[b] (2k+8)/9
[c] (k+8)/9
[d] 2*(k+8)/9
[e] none 
Ans: a 
 

9) C program code 
int zap(int n) 
{ 
if(n<=1)then zap=1; 
More 
else zap=zap(n3)+zap(n1); 
} 
then the call zap(6) gives the values of zap 
[a] 8
[b] 9
[c] 6
[d] 12
[e] 15 
Ans: b 
 
PART  B 

1) Virtual memory size depends on 
[a] address lines
[b] data bus
[c] disc space
[d] a & c [e] none 
Ans : a 
 

2) Load a 
mul a 
store t1 
load b 
mul b 
store t2 
mul t2 
add t1 
Then the content in accumulator is 
Ans : a**2+b**4 

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